http://quantlib.414.s1.nabble.com/Coupons-and-Fixed-Rate-Legs-tp1151p1169.html
Try extracting the dates array from the Schedule object. If this is correct
>From: John Maiden <
[hidden email]>
>To:
[hidden email]
>Subject: [Quantlib-users] Coupons and Fixed Rate Legs
>Date: Thu, 19 Jul 2007 19:36:57 +0000 (UTC)
>
>How exactly does the fixed rate leg work? I'm asking because I'd like to
>know
>how it determines a coupon date (and set up my own coupon dates). For
>example, I
>get a weird coupon schedule for a 4.75 fixed rate bond that goes from today
>(July 19, 2007) to February 1, 2008. Weird as in I don't understand the
>logic of
>how it was set up. Assuming that a zero coupon amount means a coupon
>payment,
>the code below gives me the following coupon dates:
>
>Aug 1, 2007
>Sept 1, 2007
>Nov 1, 2007
>Jan 1, 2008
>Feb 1, 2008
>Apr 1, 2008
>Jun 1, 2008
>Aug 1, 2008
>Sept 1, 2008
>Nov 1, 2008
>Jan 1, 2009
>Feb 1, 2009
>
>Here's the code:
>
>// TestQuantLib.cpp : Defines the entry point for the console application.
>//
>#include "stdafx.h"
>#include <ql/quantlib.hpp>
>#include <boost/timer.hpp>
>
>using namespace std;
>using namespace QuantLib;
>
>int _tmain(int argc, _TCHAR* argv[])
>{
> try{
>
> std::vector<Real> coupons(1, 0.0475);
> std::vector<Real> faceAmount_(1, 100);
>
> Calendar calendar = UnitedStates(UnitedStates::Market::NYSE);
> Date today = calendar.adjust(Date::todaysDate());
>
> BusinessDayConvention convention = Unadjusted;
>
> Frequency frequency = Daily;
>
> Date exerciseDate = Date(2, February, 2009);
>
> Schedule schedule_(today, exerciseDate, Period(frequency), calendar,
>convention, convention,
> true, false);
>
> DayCounter dayCount = Thirty360();
>
> Leg cashFlows_ = FixedRateLeg(faceAmount_, schedule_, coupons, dayCount,
> schedule_.businessDayConvention());
>
> for(int i = 0; i < cashFlows_.size(); i++){
> cout << cashFlows_[i]->amount() << endl;
> if(i % 10 == 0)
> system("PAUSE");
> }
>
> } catch (std::exception& e) {
> cout << e.what() << endl;
> }
>
> system("PAUSE");
> return 0;
>}
>
>Thanks in advance for any help.
>
>
>
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